Metamath Proof Explorer


Theorem abanssr

Description: A class abstraction with a conjunction is a subset of the class abstraction with the right conjunct only. (Contributed by AV, 7-Aug-2024) (Proof shortened by SN, 22-Aug-2024)

Ref Expression
Assertion abanssr { 𝑥 ∣ ( 𝜑 ∧ 𝜓 ) } ⊆ { 𝑥 ∣ 𝜓 }

Proof

Step Hyp Ref Expression
1 simpr ⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜓 )
2 1 ss2abi ⊢ { 𝑥 ∣ ( 𝜑 ∧ 𝜓 ) } ⊆ { 𝑥 ∣ 𝜓 }