Metamath Proof Explorer


Theorem absn

Description: Condition for a class abstraction to be a singleton. Formerly part of proof of dfiota2 . (Contributed by Andrew Salmon, 30-Jun-2011) (Revised by AV, 24-Aug-2022)

Ref Expression
Assertion absn ( { 𝑥 ∣ 𝜑 } = { 𝑌 } ↔ ∀ 𝑥 ( 𝜑 ↔ 𝑥 = 𝑌 ) )

Proof

Step Hyp Ref Expression
1 df-sn ⊢ { 𝑌 } = { 𝑥 ∣ 𝑥 = 𝑌 }
2 1 eqeq2i ⊢ ( { 𝑥 ∣ 𝜑 } = { 𝑌 } ↔ { 𝑥 ∣ 𝜑 } = { 𝑥 ∣ 𝑥 = 𝑌 } )
3 abbib ⊢ ( { 𝑥 ∣ 𝜑 } = { 𝑥 ∣ 𝑥 = 𝑌 } ↔ ∀ 𝑥 ( 𝜑 ↔ 𝑥 = 𝑌 ) )
4 2 3 bitri ⊢ ( { 𝑥 ∣ 𝜑 } = { 𝑌 } ↔ ∀ 𝑥 ( 𝜑 ↔ 𝑥 = 𝑌 ) )