Metamath Proof Explorer


Theorem addscomd

Description: Surreal addition is commutative. Part of Theorem 3 of Conway p. 17. (Contributed by Scott Fenton, 20-Aug-2024)

Ref Expression
Hypotheses addscomd.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
addscomd.2 ⊢ ( 𝜑 → 𝐵 ∈ No )
Assertion addscomd ( 𝜑 → ( 𝐴 +s 𝐵 ) = ( 𝐵 +s 𝐴 ) )

Proof

Step Hyp Ref Expression
1 addscomd.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
2 addscomd.2 ⊢ ( 𝜑 → 𝐵 ∈ No )
3 addscom ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) → ( 𝐴 +s 𝐵 ) = ( 𝐵 +s 𝐴 ) )
4 1 2 3 syl2anc ⊢ ( 𝜑 → ( 𝐴 +s 𝐵 ) = ( 𝐵 +s 𝐴 ) )