Metamath Proof Explorer


Theorem axc10

Description: Show that the original axiom ax-c10 can be derived from ax6 and axc7 (on top of propositional calculus, ax-gen , and ax-4 ). See ax6fromc10 for the rederivation of ax6 from ax-c10 .

Normally, axc10 should be used rather than ax-c10 , except by theorems specifically studying the latter's properties. See bj-axc10v for a weaker version requiring fewer axioms. (Contributed by NM, 5-Aug-1993) (Proof modification is discouraged.) Usage of this theorem is discouraged because it depends on ax-13 . (New usage is discouraged.)

Ref Expression
Assertion axc10 ( ∀ 𝑥 ( 𝑥 = 𝑦 → ∀ 𝑥 𝜑 ) → 𝜑 )

Proof

Step Hyp Ref Expression
1 ax6 ¬ ∀ 𝑥 ¬ 𝑥 = 𝑦
2 con3 ( ( 𝑥 = 𝑦 → ∀ 𝑥 𝜑 ) → ( ¬ ∀ 𝑥 𝜑 → ¬ 𝑥 = 𝑦 ) )
3 2 al2imi ( ∀ 𝑥 ( 𝑥 = 𝑦 → ∀ 𝑥 𝜑 ) → ( ∀ 𝑥 ¬ ∀ 𝑥 𝜑 → ∀ 𝑥 ¬ 𝑥 = 𝑦 ) )
4 1 3 mtoi ( ∀ 𝑥 ( 𝑥 = 𝑦 → ∀ 𝑥 𝜑 ) → ¬ ∀ 𝑥 ¬ ∀ 𝑥 𝜑 )
5 axc7 ( ¬ ∀ 𝑥 ¬ ∀ 𝑥 𝜑𝜑 )
6 4 5 syl ( ∀ 𝑥 ( 𝑥 = 𝑦 → ∀ 𝑥 𝜑 ) → 𝜑 )