Metamath Proof Explorer


Theorem axextdfeq

Description: A version of ax-ext for use with defined equality. (Contributed by Scott Fenton, 12-Dec-2010)

Ref Expression
Assertion axextdfeq ∃ 𝑧 ( ( 𝑧 ∈ 𝑥 → 𝑧 ∈ 𝑦 ) → ( ( 𝑧 ∈ 𝑦 → 𝑧 ∈ 𝑥 ) → ( 𝑥 ∈ 𝑤 → 𝑦 ∈ 𝑤 ) ) )

Proof

Step Hyp Ref Expression
1 axextnd ⊢ ∃ 𝑧 ( ( 𝑧 ∈ 𝑥 ↔ 𝑧 ∈ 𝑦 ) → 𝑥 = 𝑦 )
2 ax8 ⊢ ( 𝑥 = 𝑦 → ( 𝑥 ∈ 𝑤 → 𝑦 ∈ 𝑤 ) )
3 2 imim2i ⊢ ( ( ( 𝑧 ∈ 𝑥 ↔ 𝑧 ∈ 𝑦 ) → 𝑥 = 𝑦 ) → ( ( 𝑧 ∈ 𝑥 ↔ 𝑧 ∈ 𝑦 ) → ( 𝑥 ∈ 𝑤 → 𝑦 ∈ 𝑤 ) ) )
4 1 3 eximii ⊢ ∃ 𝑧 ( ( 𝑧 ∈ 𝑥 ↔ 𝑧 ∈ 𝑦 ) → ( 𝑥 ∈ 𝑤 → 𝑦 ∈ 𝑤 ) )
5 biimpexp ⊢ ( ( ( 𝑧 ∈ 𝑥 ↔ 𝑧 ∈ 𝑦 ) → ( 𝑥 ∈ 𝑤 → 𝑦 ∈ 𝑤 ) ) ↔ ( ( 𝑧 ∈ 𝑥 → 𝑧 ∈ 𝑦 ) → ( ( 𝑧 ∈ 𝑦 → 𝑧 ∈ 𝑥 ) → ( 𝑥 ∈ 𝑤 → 𝑦 ∈ 𝑤 ) ) ) )
6 5 exbii ⊢ ( ∃ 𝑧 ( ( 𝑧 ∈ 𝑥 ↔ 𝑧 ∈ 𝑦 ) → ( 𝑥 ∈ 𝑤 → 𝑦 ∈ 𝑤 ) ) ↔ ∃ 𝑧 ( ( 𝑧 ∈ 𝑥 → 𝑧 ∈ 𝑦 ) → ( ( 𝑧 ∈ 𝑦 → 𝑧 ∈ 𝑥 ) → ( 𝑥 ∈ 𝑤 → 𝑦 ∈ 𝑤 ) ) ) )
7 4 6 mpbi ⊢ ∃ 𝑧 ( ( 𝑧 ∈ 𝑥 → 𝑧 ∈ 𝑦 ) → ( ( 𝑧 ∈ 𝑦 → 𝑧 ∈ 𝑥 ) → ( 𝑥 ∈ 𝑤 → 𝑦 ∈ 𝑤 ) ) )