Metamath Proof Explorer
Description: 3impia with the outer implication of the hypothesis a biconditional.
(Contributed by Alan Sare, 6-Nov-2017)
|
|
Ref |
Expression |
|
Hypothesis |
bi13impia.1 |
⊢ ( ( 𝜑 ∧ 𝜓 ) ↔ ( 𝜒 → 𝜃 ) ) |
|
Assertion |
bi13impia |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜃 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
bi13impia.1 |
⊢ ( ( 𝜑 ∧ 𝜓 ) ↔ ( 𝜒 → 𝜃 ) ) |
2 |
1
|
biimpi |
⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝜒 → 𝜃 ) ) |
3 |
2
|
3impia |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜃 ) |