Metamath Proof Explorer


Theorem bj-ax89

Description: A theorem which could be used as sole axiom for the non-logical predicate instead of ax-8 and ax-9 . Indeed, it is implied over propositional calculus by the conjunction of ax-8 and ax-9 , as proved here. In the other direction, one can prove ax-8 (respectively ax-9 ) from bj-ax89 by using mpan2 (respectively mpan ) and equid . TODO: move to main part. (Contributed by BJ, 3-Oct-2019)

Ref Expression
Assertion bj-ax89 ( ( 𝑥 = 𝑦 ∧ 𝑧 = 𝑡 ) → ( 𝑥 ∈ 𝑧 → 𝑦 ∈ 𝑡 ) )

Proof

Step Hyp Ref Expression
1 ax8 ⊢ ( 𝑥 = 𝑦 → ( 𝑥 ∈ 𝑧 → 𝑦 ∈ 𝑧 ) )
2 ax9 ⊢ ( 𝑧 = 𝑡 → ( 𝑦 ∈ 𝑧 → 𝑦 ∈ 𝑡 ) )
3 1 2 sylan9 ⊢ ( ( 𝑥 = 𝑦 ∧ 𝑧 = 𝑡 ) → ( 𝑥 ∈ 𝑧 → 𝑦 ∈ 𝑡 ) )