Metamath Proof Explorer


Theorem bj-axtd

Description: This implication, proved from propositional calculus only (hence holding, up to the standard interpretation, in any modal logic), shows that the axiom scheme |- ( A. x ph -> ph ) (modal T) implies the axiom scheme |- ( A. x ph -> E. x ph ) (modal D). See also bj-axdd2 and bj-axd2d . (Contributed by BJ, 16-May-2019) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion bj-axtd ( ( ∀ 𝑥 ¬ 𝜑 → ¬ 𝜑 ) → ( ( ∀ 𝑥 𝜑𝜑 ) → ( ∀ 𝑥 𝜑 → ∃ 𝑥 𝜑 ) ) )

Proof

Step Hyp Ref Expression
1 con2 ( ( ∀ 𝑥 ¬ 𝜑 → ¬ 𝜑 ) → ( 𝜑 → ¬ ∀ 𝑥 ¬ 𝜑 ) )
2 df-ex ( ∃ 𝑥 𝜑 ↔ ¬ ∀ 𝑥 ¬ 𝜑 )
3 1 2 syl6ibr ( ( ∀ 𝑥 ¬ 𝜑 → ¬ 𝜑 ) → ( 𝜑 → ∃ 𝑥 𝜑 ) )
4 3 imim2d ( ( ∀ 𝑥 ¬ 𝜑 → ¬ 𝜑 ) → ( ( ∀ 𝑥 𝜑𝜑 ) → ( ∀ 𝑥 𝜑 → ∃ 𝑥 𝜑 ) ) )