Metamath Proof Explorer


Theorem bj-dfbi6

Description: Alternate definition of the biconditional. (Contributed by BJ, 4-Oct-2019)

Ref Expression
Assertion bj-dfbi6 ( ( 𝜑 ↔ 𝜓 ) ↔ ( ( 𝜑 ∨ 𝜓 ) ↔ ( 𝜑 ∧ 𝜓 ) ) )

Proof

Step Hyp Ref Expression
1 bj-dfbi5 ⊢ ( ( 𝜑 ↔ 𝜓 ) ↔ ( ( 𝜑 ∨ 𝜓 ) → ( 𝜑 ∧ 𝜓 ) ) )
2 id ⊢ ( ( ( 𝜑 ∨ 𝜓 ) → ( 𝜑 ∧ 𝜓 ) ) → ( ( 𝜑 ∨ 𝜓 ) → ( 𝜑 ∧ 𝜓 ) ) )
3 animorr ⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝜑 ∨ 𝜓 ) )
4 2 3 impbid1 ⊢ ( ( ( 𝜑 ∨ 𝜓 ) → ( 𝜑 ∧ 𝜓 ) ) → ( ( 𝜑 ∨ 𝜓 ) ↔ ( 𝜑 ∧ 𝜓 ) ) )
5 biimp ⊢ ( ( ( 𝜑 ∨ 𝜓 ) ↔ ( 𝜑 ∧ 𝜓 ) ) → ( ( 𝜑 ∨ 𝜓 ) → ( 𝜑 ∧ 𝜓 ) ) )
6 4 5 impbii ⊢ ( ( ( 𝜑 ∨ 𝜓 ) → ( 𝜑 ∧ 𝜓 ) ) ↔ ( ( 𝜑 ∨ 𝜓 ) ↔ ( 𝜑 ∧ 𝜓 ) ) )
7 1 6 bitri ⊢ ( ( 𝜑 ↔ 𝜓 ) ↔ ( ( 𝜑 ∨ 𝜓 ) ↔ ( 𝜑 ∧ 𝜓 ) ) )