Metamath Proof Explorer


Theorem bj-hbal

Description: More general instance of hbal . (Contributed by BJ, 4-Apr-2026)

Ref Expression
Hypothesis bj-hbal.1 ⊢ ( 𝜑 → ∀ 𝑥 𝜓 )
Assertion bj-hbal ( ∀ 𝑦 𝜑 → ∀ 𝑥 ∀ 𝑦 𝜓 )

Proof

Step Hyp Ref Expression
1 bj-hbal.1 ⊢ ( 𝜑 → ∀ 𝑥 𝜓 )
2 bj-hbalt ⊢ ( ∀ 𝑦 ( 𝜑 → ∀ 𝑥 𝜓 ) → ( ∀ 𝑦 𝜑 → ∀ 𝑥 ∀ 𝑦 𝜓 ) )
3 2 1 mpg ⊢ ( ∀ 𝑦 𝜑 → ∀ 𝑥 ∀ 𝑦 𝜓 )