Metamath Proof Explorer


Theorem bj-hbsb3

Description: Shorter proof of hbsb3 . (Contributed by BJ, 2-May-2019) (Proof modification is discouraged.)

Ref Expression
Hypothesis bj-hbsb3.1 ( 𝜑 → ∀ 𝑦 𝜑 )
Assertion bj-hbsb3 ( [ 𝑦 / 𝑥 ] 𝜑 → ∀ 𝑥 [ 𝑦 / 𝑥 ] 𝜑 )

Proof

Step Hyp Ref Expression
1 bj-hbsb3.1 ( 𝜑 → ∀ 𝑦 𝜑 )
2 bj-hbsb3t ( ∀ 𝑥 ( 𝜑 → ∀ 𝑦 𝜑 ) → ( [ 𝑦 / 𝑥 ] 𝜑 → ∀ 𝑥 [ 𝑦 / 𝑥 ] 𝜑 ) )
3 2 1 mpg ( [ 𝑦 / 𝑥 ] 𝜑 → ∀ 𝑥 [ 𝑦 / 𝑥 ] 𝜑 )