Metamath Proof Explorer


Theorem bj-nfald

Description: Variant of nfald . (Contributed by BJ, 25-Dec-2023)

Ref Expression
Hypotheses bj-nfald.1 ⊢ ( 𝜑 → ∀ 𝑦 𝜑 )
bj-nfald.2 ⊢ ( 𝜑 → Ⅎ 𝑥 𝜓 )
Assertion bj-nfald ( 𝜑 → Ⅎ 𝑥 ∀ 𝑦 𝜓 )

Proof

Step Hyp Ref Expression
1 bj-nfald.1 ⊢ ( 𝜑 → ∀ 𝑦 𝜑 )
2 bj-nfald.2 ⊢ ( 𝜑 → Ⅎ 𝑥 𝜓 )
3 19.12 ⊢ ( ∃ 𝑥 ∀ 𝑦 𝜓 → ∀ 𝑦 ∃ 𝑥 𝜓 )
4 2 nfrd ⊢ ( 𝜑 → ( ∃ 𝑥 𝜓 → ∀ 𝑥 𝜓 ) )
5 1 4 alimdh ⊢ ( 𝜑 → ( ∀ 𝑦 ∃ 𝑥 𝜓 → ∀ 𝑦 ∀ 𝑥 𝜓 ) )
6 ax-11 ⊢ ( ∀ 𝑦 ∀ 𝑥 𝜓 → ∀ 𝑥 ∀ 𝑦 𝜓 )
7 3 5 6 syl56 ⊢ ( 𝜑 → ( ∃ 𝑥 ∀ 𝑦 𝜓 → ∀ 𝑥 ∀ 𝑦 𝜓 ) )
8 7 nfd ⊢ ( 𝜑 → Ⅎ 𝑥 ∀ 𝑦 𝜓 )