Metamath Proof Explorer


Theorem bj-nfexd

Description: Variant of nfexd . (Contributed by BJ, 25-Dec-2023)

Ref Expression
Hypotheses bj-nfald.1 ⊢ ( 𝜑 → ∀ 𝑦 𝜑 )
bj-nfald.2 ⊢ ( 𝜑 → Ⅎ 𝑥 𝜓 )
Assertion bj-nfexd ( 𝜑 → Ⅎ 𝑥 ∃ 𝑦 𝜓 )

Proof

Step Hyp Ref Expression
1 bj-nfald.1 ⊢ ( 𝜑 → ∀ 𝑦 𝜑 )
2 bj-nfald.2 ⊢ ( 𝜑 → Ⅎ 𝑥 𝜓 )
3 df-ex ⊢ ( ∃ 𝑦 𝜓 ↔ ¬ ∀ 𝑦 ¬ 𝜓 )
4 2 nfnd ⊢ ( 𝜑 → Ⅎ 𝑥 ¬ 𝜓 )
5 1 4 bj-nfald ⊢ ( 𝜑 → Ⅎ 𝑥 ∀ 𝑦 ¬ 𝜓 )
6 5 nfnd ⊢ ( 𝜑 → Ⅎ 𝑥 ¬ ∀ 𝑦 ¬ 𝜓 )
7 3 6 nfxfrd ⊢ ( 𝜑 → Ⅎ 𝑥 ∃ 𝑦 𝜓 )