Metamath Proof Explorer


Theorem nfexd

Description: If x is not free in ps , it is not free in E. y ps . (Contributed by Mario Carneiro, 24-Sep-2016)

Ref Expression
Hypotheses nfald.1 𝑦 𝜑
nfald.2 ( 𝜑 → Ⅎ 𝑥 𝜓 )
Assertion nfexd ( 𝜑 → Ⅎ 𝑥𝑦 𝜓 )

Proof

Step Hyp Ref Expression
1 nfald.1 𝑦 𝜑
2 nfald.2 ( 𝜑 → Ⅎ 𝑥 𝜓 )
3 df-ex ( ∃ 𝑦 𝜓 ↔ ¬ ∀ 𝑦 ¬ 𝜓 )
4 2 nfnd ( 𝜑 → Ⅎ 𝑥 ¬ 𝜓 )
5 1 4 nfald ( 𝜑 → Ⅎ 𝑥𝑦 ¬ 𝜓 )
6 5 nfnd ( 𝜑 → Ⅎ 𝑥 ¬ ∀ 𝑦 ¬ 𝜓 )
7 3 6 nfxfrd ( 𝜑 → Ⅎ 𝑥𝑦 𝜓 )