Metamath Proof Explorer


Theorem bj-stdpc5

Description: More direct proof of stdpc5 . (Contributed by BJ, 15-Sep-2018) (Proof modification is discouraged.)

Ref Expression
Hypothesis bj-stdpc5.1 𝑥 𝜑
Assertion bj-stdpc5 ( ∀ 𝑥 ( 𝜑𝜓 ) → ( 𝜑 → ∀ 𝑥 𝜓 ) )

Proof

Step Hyp Ref Expression
1 bj-stdpc5.1 𝑥 𝜑
2 stdpc5t ( Ⅎ 𝑥 𝜑 → ( ∀ 𝑥 ( 𝜑𝜓 ) → ( 𝜑 → ∀ 𝑥 𝜓 ) ) )
3 1 2 ax-mp ( ∀ 𝑥 ( 𝜑𝜓 ) → ( 𝜑 → ∀ 𝑥 𝜓 ) )