Theorem bj-stdpc5

Description: More direct proof of stdpc5 . (Contributed by BJ, 15-Sep-2018) (Proof modification is discouraged.)

	Ref	Expression
Hypothesis	bj-stdpc5.1	|- F/ x ph
Assertion	bj-stdpc5	|- ( A. x ( ph -> ps ) -> ( ph -> A. x ps ) )

Proof

Step	Hyp	Ref	Expression
1		bj-stdpc5.1	|- F/ x ph
2		stdpc5t	|- ( F/ x ph -> ( A. x ( ph -> ps ) -> ( ph -> A. x ps ) ) )
3	1 2	ax-mp	|- ( A. x ( ph -> ps ) -> ( ph -> A. x ps ) )