Metamath Proof Explorer


Theorem bnj579

Description: Technical lemma for bnj852 . This lemma may no longer be used or have become an indirect lemma of the theorem in question (i.e. a lemma of a lemma... of the theorem). (Contributed by Jonathan Ben-Naim, 3-Jun-2011) (New usage is discouraged.)

Ref Expression
Hypotheses bnj579.1 ( 𝜑 ↔ ( 𝑓 ‘ ∅ ) = pred ( 𝑥 , 𝐴 , 𝑅 ) )
bnj579.2 ( 𝜓 ↔ ∀ 𝑖 ∈ ω ( suc 𝑖𝑛 → ( 𝑓 ‘ suc 𝑖 ) = 𝑦 ∈ ( 𝑓𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) )
bnj579.3 𝐷 = ( ω ∖ { ∅ } )
Assertion bnj579 ( 𝑛𝐷 → ∃* 𝑓 ( 𝑓 Fn 𝑛𝜑𝜓 ) )

Proof

Step Hyp Ref Expression
1 bnj579.1 ( 𝜑 ↔ ( 𝑓 ‘ ∅ ) = pred ( 𝑥 , 𝐴 , 𝑅 ) )
2 bnj579.2 ( 𝜓 ↔ ∀ 𝑖 ∈ ω ( suc 𝑖𝑛 → ( 𝑓 ‘ suc 𝑖 ) = 𝑦 ∈ ( 𝑓𝑖 ) pred ( 𝑦 , 𝐴 , 𝑅 ) ) )
3 bnj579.3 𝐷 = ( ω ∖ { ∅ } )
4 biid ( ( 𝑓 Fn 𝑛𝜑𝜓 ) ↔ ( 𝑓 Fn 𝑛𝜑𝜓 ) )
5 biid ( [ 𝑔 / 𝑓 ] 𝜑[ 𝑔 / 𝑓 ] 𝜑 )
6 biid ( [ 𝑔 / 𝑓 ] 𝜓[ 𝑔 / 𝑓 ] 𝜓 )
7 biid ( [ 𝑔 / 𝑓 ] ( 𝑓 Fn 𝑛𝜑𝜓 ) ↔ [ 𝑔 / 𝑓 ] ( 𝑓 Fn 𝑛𝜑𝜓 ) )
8 biid ( ( ( 𝑛𝐷 ∧ ( 𝑓 Fn 𝑛𝜑𝜓 ) ∧ [ 𝑔 / 𝑓 ] ( 𝑓 Fn 𝑛𝜑𝜓 ) ) → ( 𝑓𝑗 ) = ( 𝑔𝑗 ) ) ↔ ( ( 𝑛𝐷 ∧ ( 𝑓 Fn 𝑛𝜑𝜓 ) ∧ [ 𝑔 / 𝑓 ] ( 𝑓 Fn 𝑛𝜑𝜓 ) ) → ( 𝑓𝑗 ) = ( 𝑔𝑗 ) ) )
9 biid ( ∀ 𝑘𝑛 ( 𝑘 E 𝑗[ 𝑘 / 𝑗 ] ( ( 𝑛𝐷 ∧ ( 𝑓 Fn 𝑛𝜑𝜓 ) ∧ [ 𝑔 / 𝑓 ] ( 𝑓 Fn 𝑛𝜑𝜓 ) ) → ( 𝑓𝑗 ) = ( 𝑔𝑗 ) ) ) ↔ ∀ 𝑘𝑛 ( 𝑘 E 𝑗[ 𝑘 / 𝑗 ] ( ( 𝑛𝐷 ∧ ( 𝑓 Fn 𝑛𝜑𝜓 ) ∧ [ 𝑔 / 𝑓 ] ( 𝑓 Fn 𝑛𝜑𝜓 ) ) → ( 𝑓𝑗 ) = ( 𝑔𝑗 ) ) ) )
10 1 2 4 5 6 7 3 8 9 bnj580 ( 𝑛𝐷 → ∃* 𝑓 ( 𝑓 Fn 𝑛𝜑𝜓 ) )