Metamath Proof Explorer


Theorem brin

Description: The intersection of two relations. (Contributed by FL, 7-Oct-2008)

Ref Expression
Assertion brin ( 𝐴 ( 𝑅 ∩ 𝑆 ) 𝐵 ↔ ( 𝐴 𝑅 𝐵 ∧ 𝐴 𝑆 𝐵 ) )

Proof

Step Hyp Ref Expression
1 elin ⊢ ( ⟨ 𝐴 , 𝐵 ⟩ ∈ ( 𝑅 ∩ 𝑆 ) ↔ ( ⟨ 𝐴 , 𝐵 ⟩ ∈ 𝑅 ∧ ⟨ 𝐴 , 𝐵 ⟩ ∈ 𝑆 ) )
2 df-br ⊢ ( 𝐴 ( 𝑅 ∩ 𝑆 ) 𝐵 ↔ ⟨ 𝐴 , 𝐵 ⟩ ∈ ( 𝑅 ∩ 𝑆 ) )
3 df-br ⊢ ( 𝐴 𝑅 𝐵 ↔ ⟨ 𝐴 , 𝐵 ⟩ ∈ 𝑅 )
4 df-br ⊢ ( 𝐴 𝑆 𝐵 ↔ ⟨ 𝐴 , 𝐵 ⟩ ∈ 𝑆 )
5 3 4 anbi12i ⊢ ( ( 𝐴 𝑅 𝐵 ∧ 𝐴 𝑆 𝐵 ) ↔ ( ⟨ 𝐴 , 𝐵 ⟩ ∈ 𝑅 ∧ ⟨ 𝐴 , 𝐵 ⟩ ∈ 𝑆 ) )
6 1 2 5 3bitr4i ⊢ ( 𝐴 ( 𝑅 ∩ 𝑆 ) 𝐵 ↔ ( 𝐴 𝑅 𝐵 ∧ 𝐴 𝑆 𝐵 ) )