Metamath Proof Explorer


Theorem cgranbtwn

Description: Null angle implies betweenness. (Contributed by SS, 4-Jun-2026)

Ref Expression
Hypotheses cgranbtwn.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
cgranbtwn.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
cgranbtwn.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
cgranbtwn.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
cgranbtwn.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
cgranbtwn.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
cgranbtwn.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑃 )
cgranbtwn.e ⊢ ( 𝜑 → 𝐸 ∈ 𝑃 )
cgranbtwn.f ⊢ ( 𝜑 → 𝐹 ∈ 𝑃 )
cgranbtwn.1 ⊢ ( 𝜑 → ⟨“ 𝐴 𝐵 𝐶 ”⟩ ( cgrA ‘ 𝐺 ) ⟨“ 𝐷 𝐸 𝐹 ”⟩ )
cgranbtwn.2 ⊢ ( 𝜑 → 𝐴 ∈ ( 𝐵 𝐼 𝐶 ) )
Assertion cgranbtwn ( 𝜑 → ( 𝐷 ∈ ( 𝐸 𝐼 𝐹 ) ∨ 𝐹 ∈ ( 𝐸 𝐼 𝐷 ) ) )

Proof

Step Hyp Ref Expression
1 cgranbtwn.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
2 cgranbtwn.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
3 cgranbtwn.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
4 cgranbtwn.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
5 cgranbtwn.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
6 cgranbtwn.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
7 cgranbtwn.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑃 )
8 cgranbtwn.e ⊢ ( 𝜑 → 𝐸 ∈ 𝑃 )
9 cgranbtwn.f ⊢ ( 𝜑 → 𝐹 ∈ 𝑃 )
10 cgranbtwn.1 ⊢ ( 𝜑 → ⟨“ 𝐴 𝐵 𝐶 ”⟩ ( cgrA ‘ 𝐺 ) ⟨“ 𝐷 𝐸 𝐹 ”⟩ )
11 cgranbtwn.2 ⊢ ( 𝜑 → 𝐴 ∈ ( 𝐵 𝐼 𝐶 ) )
12 eqid ⊢ ( dist ‘ 𝐺 ) = ( dist ‘ 𝐺 )
13 eqid ⊢ ( hlG ‘ 𝐺 ) = ( hlG ‘ 𝐺 )
14 1 2 13 3 4 5 6 7 8 9 10 cgrane2 ⊢ ( 𝜑 → 𝐵 ≠ 𝐶 )
15 1 2 13 3 4 5 6 7 8 9 10 cgrane1 ⊢ ( 𝜑 → 𝐴 ≠ 𝐵 )
16 1 2 13 5 6 4 3 4 11 14 15 btwnhl1 ⊢ ( 𝜑 → 𝐴 ( ( hlG ‘ 𝐺 ) ‘ 𝐵 ) 𝐶 )
17 1 2 12 3 4 5 6 7 8 9 10 13 16 cgrahl ⊢ ( 𝜑 → 𝐷 ( ( hlG ‘ 𝐺 ) ‘ 𝐸 ) 𝐹 )
18 1 2 13 7 9 8 3 ishlg ⊢ ( 𝜑 → ( 𝐷 ( ( hlG ‘ 𝐺 ) ‘ 𝐸 ) 𝐹 ↔ ( 𝐷 ≠ 𝐸 ∧ 𝐹 ≠ 𝐸 ∧ ( 𝐷 ∈ ( 𝐸 𝐼 𝐹 ) ∨ 𝐹 ∈ ( 𝐸 𝐼 𝐷 ) ) ) ) )
19 17 18 mpbid ⊢ ( 𝜑 → ( 𝐷 ≠ 𝐸 ∧ 𝐹 ≠ 𝐸 ∧ ( 𝐷 ∈ ( 𝐸 𝐼 𝐹 ) ∨ 𝐹 ∈ ( 𝐸 𝐼 𝐷 ) ) ) )
20 19 simp3d ⊢ ( 𝜑 → ( 𝐷 ∈ ( 𝐸 𝐼 𝐹 ) ∨ 𝐹 ∈ ( 𝐸 𝐼 𝐷 ) ) )