Metamath Proof Explorer


Theorem cgranbtwn

Description: Null angle implies betweenness. (Contributed by SS, 4-Jun-2026)

Ref Expression
Hypotheses cgranbtwn.p
|- P = ( Base ` G )
cgranbtwn.i
|- I = ( Itv ` G )
cgranbtwn.g
|- ( ph -> G e. TarskiG )
cgranbtwn.a
|- ( ph -> A e. P )
cgranbtwn.b
|- ( ph -> B e. P )
cgranbtwn.c
|- ( ph -> C e. P )
cgranbtwn.d
|- ( ph -> D e. P )
cgranbtwn.e
|- ( ph -> E e. P )
cgranbtwn.f
|- ( ph -> F e. P )
cgranbtwn.1
|- ( ph -> <" A B C "> ( cgrA ` G ) <" D E F "> )
cgranbtwn.2
|- ( ph -> A e. ( B I C ) )
Assertion cgranbtwn
|- ( ph -> ( D e. ( E I F ) \/ F e. ( E I D ) ) )

Proof

Step Hyp Ref Expression
1 cgranbtwn.p
 |-  P = ( Base ` G )
2 cgranbtwn.i
 |-  I = ( Itv ` G )
3 cgranbtwn.g
 |-  ( ph -> G e. TarskiG )
4 cgranbtwn.a
 |-  ( ph -> A e. P )
5 cgranbtwn.b
 |-  ( ph -> B e. P )
6 cgranbtwn.c
 |-  ( ph -> C e. P )
7 cgranbtwn.d
 |-  ( ph -> D e. P )
8 cgranbtwn.e
 |-  ( ph -> E e. P )
9 cgranbtwn.f
 |-  ( ph -> F e. P )
10 cgranbtwn.1
 |-  ( ph -> <" A B C "> ( cgrA ` G ) <" D E F "> )
11 cgranbtwn.2
 |-  ( ph -> A e. ( B I C ) )
12 eqid
 |-  ( dist ` G ) = ( dist ` G )
13 eqid
 |-  ( hlG ` G ) = ( hlG ` G )
14 1 2 13 3 4 5 6 7 8 9 10 cgrane2
 |-  ( ph -> B =/= C )
15 1 2 13 3 4 5 6 7 8 9 10 cgrane1
 |-  ( ph -> A =/= B )
16 1 2 13 5 6 4 3 4 11 14 15 btwnhl1
 |-  ( ph -> A ( ( hlG ` G ) ` B ) C )
17 1 2 12 3 4 5 6 7 8 9 10 13 16 cgrahl
 |-  ( ph -> D ( ( hlG ` G ) ` E ) F )
18 1 2 13 7 9 8 3 ishlg
 |-  ( ph -> ( D ( ( hlG ` G ) ` E ) F <-> ( D =/= E /\ F =/= E /\ ( D e. ( E I F ) \/ F e. ( E I D ) ) ) ) )
19 17 18 mpbid
 |-  ( ph -> ( D =/= E /\ F =/= E /\ ( D e. ( E I F ) \/ F e. ( E I D ) ) ) )
20 19 simp3d
 |-  ( ph -> ( D e. ( E I F ) \/ F e. ( E I D ) ) )