Metamath Proof Explorer


Theorem clm1

Description: The identity of the scalar ring of a subcomplex module. (Contributed by Mario Carneiro, 16-Oct-2015)

Ref Expression
Hypothesis clm0.f 𝐹 = ( Scalar ‘ 𝑊 )
Assertion clm1 ( 𝑊 ∈ ℂMod → 1 = ( 1r𝐹 ) )

Proof

Step Hyp Ref Expression
1 clm0.f 𝐹 = ( Scalar ‘ 𝑊 )
2 eqid ( Base ‘ 𝐹 ) = ( Base ‘ 𝐹 )
3 1 2 clmsubrg ( 𝑊 ∈ ℂMod → ( Base ‘ 𝐹 ) ∈ ( SubRing ‘ ℂfld ) )
4 eqid ( ℂflds ( Base ‘ 𝐹 ) ) = ( ℂflds ( Base ‘ 𝐹 ) )
5 cnfld1 1 = ( 1r ‘ ℂfld )
6 4 5 subrg1 ( ( Base ‘ 𝐹 ) ∈ ( SubRing ‘ ℂfld ) → 1 = ( 1r ‘ ( ℂflds ( Base ‘ 𝐹 ) ) ) )
7 3 6 syl ( 𝑊 ∈ ℂMod → 1 = ( 1r ‘ ( ℂflds ( Base ‘ 𝐹 ) ) ) )
8 1 2 clmsca ( 𝑊 ∈ ℂMod → 𝐹 = ( ℂflds ( Base ‘ 𝐹 ) ) )
9 8 fveq2d ( 𝑊 ∈ ℂMod → ( 1r𝐹 ) = ( 1r ‘ ( ℂflds ( Base ‘ 𝐹 ) ) ) )
10 7 9 eqtr4d ( 𝑊 ∈ ℂMod → 1 = ( 1r𝐹 ) )