Metamath Proof Explorer


Theorem cnveq0

Description: A relation empty iff its converse is empty. (Contributed by FL, 19-Sep-2011)

Ref Expression
Assertion cnveq0 ( Rel 𝐴 → ( 𝐴 = ∅ ↔ 𝐴 = ∅ ) )

Proof

Step Hyp Ref Expression
1 cnv0 ∅ = ∅
2 rel0 Rel ∅
3 cnveqb ( ( Rel 𝐴 ∧ Rel ∅ ) → ( 𝐴 = ∅ ↔ 𝐴 = ∅ ) )
4 2 3 mpan2 ( Rel 𝐴 → ( 𝐴 = ∅ ↔ 𝐴 = ∅ ) )
5 eqeq2 ( ∅ = ∅ → ( 𝐴 = ∅ ↔ 𝐴 = ∅ ) )
6 5 bibi2d ( ∅ = ∅ → ( ( 𝐴 = ∅ ↔ 𝐴 = ∅ ) ↔ ( 𝐴 = ∅ ↔ 𝐴 = ∅ ) ) )
7 4 6 syl5ibr ( ∅ = ∅ → ( Rel 𝐴 → ( 𝐴 = ∅ ↔ 𝐴 = ∅ ) ) )
8 7 eqcoms ( ∅ = ∅ → ( Rel 𝐴 → ( 𝐴 = ∅ ↔ 𝐴 = ∅ ) ) )
9 1 8 ax-mp ( Rel 𝐴 → ( 𝐴 = ∅ ↔ 𝐴 = ∅ ) )