Metamath Proof Explorer


Theorem cnvso

Description: The converse of a strict order relation is a strict order relation. (Contributed by NM, 15-Jun-2005)

Ref Expression
Assertion cnvso ( 𝑅 Or 𝐴 ↔ ◡ 𝑅 Or 𝐴 )

Proof

Step Hyp Ref Expression
1 cnvpo ⊢ ( 𝑅 Po 𝐴 ↔ ◡ 𝑅 Po 𝐴 )
2 ralcom ⊢ ( ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ 𝐴 ( 𝑥 𝑅 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 𝑅 𝑥 ) ↔ ∀ 𝑦 ∈ 𝐴 ∀ 𝑥 ∈ 𝐴 ( 𝑥 𝑅 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 𝑅 𝑥 ) )
3 vex ⊢ 𝑦 ∈ V
4 vex ⊢ 𝑥 ∈ V
5 3 4 brcnv ⊢ ( 𝑦 ◡ 𝑅 𝑥 ↔ 𝑥 𝑅 𝑦 )
6 equcom ⊢ ( 𝑦 = 𝑥 ↔ 𝑥 = 𝑦 )
7 4 3 brcnv ⊢ ( 𝑥 ◡ 𝑅 𝑦 ↔ 𝑦 𝑅 𝑥 )
8 5 6 7 3orbi123i ⊢ ( ( 𝑦 ◡ 𝑅 𝑥 ∨ 𝑦 = 𝑥 ∨ 𝑥 ◡ 𝑅 𝑦 ) ↔ ( 𝑥 𝑅 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 𝑅 𝑥 ) )
9 8 2ralbii ⊢ ( ∀ 𝑦 ∈ 𝐴 ∀ 𝑥 ∈ 𝐴 ( 𝑦 ◡ 𝑅 𝑥 ∨ 𝑦 = 𝑥 ∨ 𝑥 ◡ 𝑅 𝑦 ) ↔ ∀ 𝑦 ∈ 𝐴 ∀ 𝑥 ∈ 𝐴 ( 𝑥 𝑅 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 𝑅 𝑥 ) )
10 2 9 bitr4i ⊢ ( ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ 𝐴 ( 𝑥 𝑅 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 𝑅 𝑥 ) ↔ ∀ 𝑦 ∈ 𝐴 ∀ 𝑥 ∈ 𝐴 ( 𝑦 ◡ 𝑅 𝑥 ∨ 𝑦 = 𝑥 ∨ 𝑥 ◡ 𝑅 𝑦 ) )
11 1 10 anbi12i ⊢ ( ( 𝑅 Po 𝐴 ∧ ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ 𝐴 ( 𝑥 𝑅 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 𝑅 𝑥 ) ) ↔ ( ◡ 𝑅 Po 𝐴 ∧ ∀ 𝑦 ∈ 𝐴 ∀ 𝑥 ∈ 𝐴 ( 𝑦 ◡ 𝑅 𝑥 ∨ 𝑦 = 𝑥 ∨ 𝑥 ◡ 𝑅 𝑦 ) ) )
12 df-so ⊢ ( 𝑅 Or 𝐴 ↔ ( 𝑅 Po 𝐴 ∧ ∀ 𝑥 ∈ 𝐴 ∀ 𝑦 ∈ 𝐴 ( 𝑥 𝑅 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 𝑅 𝑥 ) ) )
13 df-so ⊢ ( ◡ 𝑅 Or 𝐴 ↔ ( ◡ 𝑅 Po 𝐴 ∧ ∀ 𝑦 ∈ 𝐴 ∀ 𝑥 ∈ 𝐴 ( 𝑦 ◡ 𝑅 𝑥 ∨ 𝑦 = 𝑥 ∨ 𝑥 ◡ 𝑅 𝑦 ) ) )
14 11 12 13 3bitr4i ⊢ ( 𝑅 Or 𝐴 ↔ ◡ 𝑅 Or 𝐴 )