Metamath Proof Explorer


Theorem coep

Description: Composition with the membership relation. (Contributed by Scott Fenton, 18-Feb-2013)

Ref Expression
Hypotheses coep.1 ⊢ 𝐴 ∈ V
coep.2 ⊢ 𝐵 ∈ V
Assertion coep ( 𝐴 ( E ∘ 𝑅 ) 𝐵 ↔ ∃ 𝑥 ∈ 𝐵 𝐴 𝑅 𝑥 )

Proof

Step Hyp Ref Expression
1 coep.1 ⊢ 𝐴 ∈ V
2 coep.2 ⊢ 𝐵 ∈ V
3 2 epeli ⊢ ( 𝑥 E 𝐵 ↔ 𝑥 ∈ 𝐵 )
4 3 anbi1ci ⊢ ( ( 𝐴 𝑅 𝑥 ∧ 𝑥 E 𝐵 ) ↔ ( 𝑥 ∈ 𝐵 ∧ 𝐴 𝑅 𝑥 ) )
5 4 exbii ⊢ ( ∃ 𝑥 ( 𝐴 𝑅 𝑥 ∧ 𝑥 E 𝐵 ) ↔ ∃ 𝑥 ( 𝑥 ∈ 𝐵 ∧ 𝐴 𝑅 𝑥 ) )
6 1 2 brco ⊢ ( 𝐴 ( E ∘ 𝑅 ) 𝐵 ↔ ∃ 𝑥 ( 𝐴 𝑅 𝑥 ∧ 𝑥 E 𝐵 ) )
7 df-rex ⊢ ( ∃ 𝑥 ∈ 𝐵 𝐴 𝑅 𝑥 ↔ ∃ 𝑥 ( 𝑥 ∈ 𝐵 ∧ 𝐴 𝑅 𝑥 ) )
8 5 6 7 3bitr4i ⊢ ( 𝐴 ( E ∘ 𝑅 ) 𝐵 ↔ ∃ 𝑥 ∈ 𝐵 𝐴 𝑅 𝑥 )