Metamath Proof Explorer


Theorem coeq1i

Description: Equality inference for composition of two classes. (Contributed by NM, 16-Nov-2000)

Ref Expression
Hypothesis coeq1i.1 𝐴 = 𝐵
Assertion coeq1i ( 𝐴𝐶 ) = ( 𝐵𝐶 )

Proof

Step Hyp Ref Expression
1 coeq1i.1 𝐴 = 𝐵
2 coeq1 ( 𝐴 = 𝐵 → ( 𝐴𝐶 ) = ( 𝐵𝐶 ) )
3 1 2 ax-mp ( 𝐴𝐶 ) = ( 𝐵𝐶 )