Metamath Proof Explorer


Theorem coeq1i

Description: Equality inference for composition of two classes. (Contributed by NM, 16-Nov-2000)

Ref Expression
Hypothesis coeq1i.1 ⊢ 𝐴 = 𝐵
Assertion coeq1i ( 𝐴 ∘ 𝐶 ) = ( 𝐵 ∘ 𝐶 )

Proof

Step Hyp Ref Expression
1 coeq1i.1 ⊢ 𝐴 = 𝐵
2 coeq1 ⊢ ( 𝐴 = 𝐵 → ( 𝐴 ∘ 𝐶 ) = ( 𝐵 ∘ 𝐶 ) )
3 1 2 ax-mp ⊢ ( 𝐴 ∘ 𝐶 ) = ( 𝐵 ∘ 𝐶 )