Metamath Proof Explorer


Theorem coideq

Description: Equality theorem for composition of two classes. (Contributed by Peter Mazsa, 23-Sep-2021)

Ref Expression
Assertion coideq ( 𝐴 = 𝐵 → ( 𝐴 ∘ 𝐴 ) = ( 𝐵 ∘ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 coeq1 ⊢ ( 𝐴 = 𝐵 → ( 𝐴 ∘ 𝐴 ) = ( 𝐵 ∘ 𝐴 ) )
2 coeq2 ⊢ ( 𝐴 = 𝐵 → ( 𝐵 ∘ 𝐴 ) = ( 𝐵 ∘ 𝐵 ) )
3 1 2 eqtrd ⊢ ( 𝐴 = 𝐵 → ( 𝐴 ∘ 𝐴 ) = ( 𝐵 ∘ 𝐵 ) )