Metamath Proof Explorer


Theorem colleq1

Description: Equality theorem for the collection operation. (Contributed by Rohan Ridenour, 11-Aug-2023)

Ref Expression
Assertion colleq1 ( 𝐹 = 𝐺 → ( 𝐹 Coll 𝐴 ) = ( 𝐺 Coll 𝐴 ) )

Proof

Step Hyp Ref Expression
1 id ( 𝐹 = 𝐺𝐹 = 𝐺 )
2 eqidd ( 𝐹 = 𝐺𝐴 = 𝐴 )
3 1 2 colleq12d ( 𝐹 = 𝐺 → ( 𝐹 Coll 𝐴 ) = ( 𝐺 Coll 𝐴 ) )