Metamath Proof Explorer
Description: A space where every open cover has an A refinement is a topological
space. (Contributed by Thierry Arnoux, 7-Jan-2020)
|
|
Ref |
Expression |
|
Assertion |
creftop |
⊢ ( 𝐽 ∈ CovHasRef 𝐴 → 𝐽 ∈ Top ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
eqid |
⊢ ∪ 𝐽 = ∪ 𝐽 |
2 |
1
|
iscref |
⊢ ( 𝐽 ∈ CovHasRef 𝐴 ↔ ( 𝐽 ∈ Top ∧ ∀ 𝑦 ∈ 𝒫 𝐽 ( ∪ 𝐽 = ∪ 𝑦 → ∃ 𝑧 ∈ ( 𝒫 𝐽 ∩ 𝐴 ) 𝑧 Ref 𝑦 ) ) ) |
3 |
2
|
simplbi |
⊢ ( 𝐽 ∈ CovHasRef 𝐴 → 𝐽 ∈ Top ) |