Metamath Proof Explorer


Theorem csbmpt2

Description: Move substitution into the second part of a maps-to notation. (Contributed by AV, 26-Sep-2019)

Ref Expression
Assertion csbmpt2 ( 𝐴 ∈ 𝑉 → ⦋ 𝐴 / 𝑥 ⦌ ( 𝑦 ∈ 𝑌 ↦ 𝑍 ) = ( 𝑦 ∈ 𝑌 ↦ ⦋ 𝐴 / 𝑥 ⦌ 𝑍 ) )

Proof

Step Hyp Ref Expression
1 csbmpt12 ⊢ ( 𝐴 ∈ 𝑉 → ⦋ 𝐴 / 𝑥 ⦌ ( 𝑦 ∈ 𝑌 ↦ 𝑍 ) = ( 𝑦 ∈ ⦋ 𝐴 / 𝑥 ⦌ 𝑌 ↦ ⦋ 𝐴 / 𝑥 ⦌ 𝑍 ) )
2 csbconstg ⊢ ( 𝐴 ∈ 𝑉 → ⦋ 𝐴 / 𝑥 ⦌ 𝑌 = 𝑌 )
3 2 mpteq1d ⊢ ( 𝐴 ∈ 𝑉 → ( 𝑦 ∈ ⦋ 𝐴 / 𝑥 ⦌ 𝑌 ↦ ⦋ 𝐴 / 𝑥 ⦌ 𝑍 ) = ( 𝑦 ∈ 𝑌 ↦ ⦋ 𝐴 / 𝑥 ⦌ 𝑍 ) )
4 1 3 eqtrd ⊢ ( 𝐴 ∈ 𝑉 → ⦋ 𝐴 / 𝑥 ⦌ ( 𝑦 ∈ 𝑌 ↦ 𝑍 ) = ( 𝑦 ∈ 𝑌 ↦ ⦋ 𝐴 / 𝑥 ⦌ 𝑍 ) )