Metamath Proof Explorer


Theorem cvsclm

Description: A subcomplex vector space is a subcomplex module. (Contributed by Thierry Arnoux, 22-May-2019)

Ref Expression
Hypothesis cvslvec.1 ⊢ ( 𝜑 → 𝑊 ∈ ℂVec )
Assertion cvsclm ( 𝜑 → 𝑊 ∈ ℂMod )

Proof

Step Hyp Ref Expression
1 cvslvec.1 ⊢ ( 𝜑 → 𝑊 ∈ ℂVec )
2 df-cvs ⊢ ℂVec = ( ℂMod ∩ LVec )
3 2 elin2 ⊢ ( 𝑊 ∈ ℂVec ↔ ( 𝑊 ∈ ℂMod ∧ 𝑊 ∈ LVec ) )
4 3 simplbi ⊢ ( 𝑊 ∈ ℂVec → 𝑊 ∈ ℂMod )
5 1 4 syl ⊢ ( 𝜑 → 𝑊 ∈ ℂMod )