Metamath Proof Explorer


Definition df-bits

Description: Define the binary bits of an integer. The expression M e. ( bitsN ) means that the M -th bit of N is 1 (and its negation means the bit is 0). (Contributed by Mario Carneiro, 4-Sep-2016)

Ref Expression
Assertion df-bits bits = ( 𝑛 ∈ ℤ ↦ { 𝑚 ∈ ℕ0 ∣ ¬ 2 ∥ ( ⌊ ‘ ( 𝑛 / ( 2 ↑ 𝑚 ) ) ) } )

Detailed syntax breakdown

Step Hyp Ref Expression
0 cbits ⊢ bits
1 vn ⊢ 𝑛
2 cz ⊢ ℤ
3 vm ⊢ 𝑚
4 cn0 ⊢ ℕ0
5 c2 ⊢ 2
6 cdvds ⊢ ∥
7 cfl ⊢ ⌊
8 1 cv ⊢ 𝑛
9 cdiv ⊢ /
10 cexp ⊢ ↑
11 3 cv ⊢ 𝑚
12 5 11 10 co ⊢ ( 2 ↑ 𝑚 )
13 8 12 9 co ⊢ ( 𝑛 / ( 2 ↑ 𝑚 ) )
14 13 7 cfv ⊢ ( ⌊ ‘ ( 𝑛 / ( 2 ↑ 𝑚 ) ) )
15 5 14 6 wbr ⊢ 2 ∥ ( ⌊ ‘ ( 𝑛 / ( 2 ↑ 𝑚 ) ) )
16 15 wn ⊢ ¬ 2 ∥ ( ⌊ ‘ ( 𝑛 / ( 2 ↑ 𝑚 ) ) )
17 16 3 4 crab ⊢ { 𝑚 ∈ ℕ0 ∣ ¬ 2 ∥ ( ⌊ ‘ ( 𝑛 / ( 2 ↑ 𝑚 ) ) ) }
18 1 2 17 cmpt ⊢ ( 𝑛 ∈ ℤ ↦ { 𝑚 ∈ ℕ0 ∣ ¬ 2 ∥ ( ⌊ ‘ ( 𝑛 / ( 2 ↑ 𝑚 ) ) ) } )
19 0 18 wceq ⊢ bits = ( 𝑛 ∈ ℤ ↦ { 𝑚 ∈ ℕ0 ∣ ¬ 2 ∥ ( ⌊ ‘ ( 𝑛 / ( 2 ↑ 𝑚 ) ) ) } )