Metamath Proof Explorer


Definition df-bj-oppc

Description: Define the negation (operation giving the opposite) on the set of extended complex numbers and the complex projective line (Riemann sphere). (Contributed by BJ, 22-Jun-2019)

Ref Expression
Assertion df-bj-oppc -ℂ̅ = ( 𝑥 ∈ ( ℂ̅ ∪ ℂ̂ ) ↦ if ( 𝑥 = ∞ , ∞ , if ( 𝑥 ∈ ℂ , ( ℩ 𝑦 ∈ ℂ ( 𝑥 +ℂ̅ 𝑦 ) = 0 ) , ( +∞eiτ ‘ ( 𝑥 +ℂ̅ ⟨ 1/2 , 0R ⟩ ) ) ) ) )

Detailed syntax breakdown

Step Hyp Ref Expression
0 coppcc ⊢ -ℂ̅
1 vx ⊢ 𝑥
2 cccbar ⊢ ℂ̅
3 ccchat ⊢ ℂ̂
4 2 3 cun ⊢ ( ℂ̅ ∪ ℂ̂ )
5 1 cv ⊢ 𝑥
6 cinfty ⊢ ∞
7 5 6 wceq ⊢ 𝑥 = ∞
8 cc ⊢ ℂ
9 5 8 wcel ⊢ 𝑥 ∈ ℂ
10 vy ⊢ 𝑦
11 caddcc ⊢ +ℂ̅
12 10 cv ⊢ 𝑦
13 5 12 11 co ⊢ ( 𝑥 +ℂ̅ 𝑦 )
14 cc0 ⊢ 0
15 13 14 wceq ⊢ ( 𝑥 +ℂ̅ 𝑦 ) = 0
16 15 10 8 crio ⊢ ( ℩ 𝑦 ∈ ℂ ( 𝑥 +ℂ̅ 𝑦 ) = 0 )
17 cinftyexpitau ⊢ +∞eiτ
18 chalf ⊢ 1/2
19 c0r ⊢ 0R
20 18 19 cop ⊢ ⟨ 1/2 , 0R ⟩
21 5 20 11 co ⊢ ( 𝑥 +ℂ̅ ⟨ 1/2 , 0R ⟩ )
22 21 17 cfv ⊢ ( +∞eiτ ‘ ( 𝑥 +ℂ̅ ⟨ 1/2 , 0R ⟩ ) )
23 9 16 22 cif ⊢ if ( 𝑥 ∈ ℂ , ( ℩ 𝑦 ∈ ℂ ( 𝑥 +ℂ̅ 𝑦 ) = 0 ) , ( +∞eiτ ‘ ( 𝑥 +ℂ̅ ⟨ 1/2 , 0R ⟩ ) ) )
24 7 6 23 cif ⊢ if ( 𝑥 = ∞ , ∞ , if ( 𝑥 ∈ ℂ , ( ℩ 𝑦 ∈ ℂ ( 𝑥 +ℂ̅ 𝑦 ) = 0 ) , ( +∞eiτ ‘ ( 𝑥 +ℂ̅ ⟨ 1/2 , 0R ⟩ ) ) ) )
25 1 4 24 cmpt ⊢ ( 𝑥 ∈ ( ℂ̅ ∪ ℂ̂ ) ↦ if ( 𝑥 = ∞ , ∞ , if ( 𝑥 ∈ ℂ , ( ℩ 𝑦 ∈ ℂ ( 𝑥 +ℂ̅ 𝑦 ) = 0 ) , ( +∞eiτ ‘ ( 𝑥 +ℂ̅ ⟨ 1/2 , 0R ⟩ ) ) ) ) )
26 0 25 wceq ⊢ -ℂ̅ = ( 𝑥 ∈ ( ℂ̅ ∪ ℂ̂ ) ↦ if ( 𝑥 = ∞ , ∞ , if ( 𝑥 ∈ ℂ , ( ℩ 𝑦 ∈ ℂ ( 𝑥 +ℂ̅ 𝑦 ) = 0 ) , ( +∞eiτ ‘ ( 𝑥 +ℂ̅ ⟨ 1/2 , 0R ⟩ ) ) ) ) )