Metamath Proof Explorer


Definition df-mesyn

Description: Define the syntax typecode function for expressions. (Contributed by Mario Carneiro, 12-Jun-2023)

Ref Expression
Assertion df-mesyn mESyn = ( 𝑡 ∈ V ↦ ( 𝑐 ∈ ( mTC ‘ 𝑡 ) , 𝑒 ∈ ( mREx ‘ 𝑡 ) ↦ ( ( ( mSyn ‘ 𝑡 ) ‘ 𝑐 ) m0St 𝑒 ) ) )

Detailed syntax breakdown

Step Hyp Ref Expression
0 cmesy ⊢ mESyn
1 vt ⊢ 𝑡
2 cvv ⊢ V
3 vc ⊢ 𝑐
4 cmtc ⊢ mTC
5 1 cv ⊢ 𝑡
6 5 4 cfv ⊢ ( mTC ‘ 𝑡 )
7 ve ⊢ 𝑒
8 cmrex ⊢ mREx
9 5 8 cfv ⊢ ( mREx ‘ 𝑡 )
10 cmsy ⊢ mSyn
11 5 10 cfv ⊢ ( mSyn ‘ 𝑡 )
12 3 cv ⊢ 𝑐
13 12 11 cfv ⊢ ( ( mSyn ‘ 𝑡 ) ‘ 𝑐 )
14 cm0s ⊢ m0St
15 7 cv ⊢ 𝑒
16 13 15 14 co ⊢ ( ( ( mSyn ‘ 𝑡 ) ‘ 𝑐 ) m0St 𝑒 )
17 3 7 6 9 16 cmpo ⊢ ( 𝑐 ∈ ( mTC ‘ 𝑡 ) , 𝑒 ∈ ( mREx ‘ 𝑡 ) ↦ ( ( ( mSyn ‘ 𝑡 ) ‘ 𝑐 ) m0St 𝑒 ) )
18 1 2 17 cmpt ⊢ ( 𝑡 ∈ V ↦ ( 𝑐 ∈ ( mTC ‘ 𝑡 ) , 𝑒 ∈ ( mREx ‘ 𝑡 ) ↦ ( ( ( mSyn ‘ 𝑡 ) ‘ 𝑐 ) m0St 𝑒 ) ) )
19 0 18 wceq ⊢ mESyn = ( 𝑡 ∈ V ↦ ( 𝑐 ∈ ( mTC ‘ 𝑡 ) , 𝑒 ∈ ( mREx ‘ 𝑡 ) ↦ ( ( ( mSyn ‘ 𝑡 ) ‘ 𝑐 ) m0St 𝑒 ) ) )