Metamath Proof Explorer


Theorem dfmember2

Description: Alternate definition of the membership equivalence relation. (Contributed by Peter Mazsa, 25-Sep-2021)

Ref Expression
Assertion dfmember2 ( MembEr 𝐴 ↔ ( EqvRel ∼ 𝐴 ∧ ( dom ∼ 𝐴 /𝐴 ) = 𝐴 ) )

Proof

Step Hyp Ref Expression
1 dfmember ( MembEr 𝐴 ↔ ∼ 𝐴 ErALTV 𝐴 )
2 dferALTV2 ( ∼ 𝐴 ErALTV 𝐴 ↔ ( EqvRel ∼ 𝐴 ∧ ( dom ∼ 𝐴 /𝐴 ) = 𝐴 ) )
3 1 2 bitri ( MembEr 𝐴 ↔ ( EqvRel ∼ 𝐴 ∧ ( dom ∼ 𝐴 /𝐴 ) = 𝐴 ) )