Metamath Proof Explorer


Theorem dfric2

Description: Alternate definition of the ring isomorphism relation. (Contributed by Jeff Madsen, 16-Jun-2011) (Revised by AV, 23-Aug-2026)

Ref Expression
Assertion dfric2 𝑟 = { ⟨ 𝑟 , 𝑠 ⟩ ∣ ( ( 𝑟 ∈ Ring ∧ 𝑠 ∈ Ring ) ∧ ∃ 𝑓 𝑓 ∈ ( 𝑟 RingIso 𝑠 ) ) }

Proof

Step Hyp Ref Expression
1 isbrric2 ( 𝑟𝑟 𝑠 ↔ ( ( 𝑟 ∈ Ring ∧ 𝑠 ∈ Ring ) ∧ ∃ 𝑓 𝑓 ∈ ( 𝑟 RingIso 𝑠 ) ) )
2 1 anbi2i ( ( 𝑥 = ⟨ 𝑟 , 𝑠 ⟩ ∧ 𝑟𝑟 𝑠 ) ↔ ( 𝑥 = ⟨ 𝑟 , 𝑠 ⟩ ∧ ( ( 𝑟 ∈ Ring ∧ 𝑠 ∈ Ring ) ∧ ∃ 𝑓 𝑓 ∈ ( 𝑟 RingIso 𝑠 ) ) ) )
3 2 2exbii ( ∃ 𝑟𝑠 ( 𝑥 = ⟨ 𝑟 , 𝑠 ⟩ ∧ 𝑟𝑟 𝑠 ) ↔ ∃ 𝑟𝑠 ( 𝑥 = ⟨ 𝑟 , 𝑠 ⟩ ∧ ( ( 𝑟 ∈ Ring ∧ 𝑠 ∈ Ring ) ∧ ∃ 𝑓 𝑓 ∈ ( 𝑟 RingIso 𝑠 ) ) ) )
4 ricrel Rel ≃𝑟
5 elrelb ( Rel ≃𝑟 → ( 𝑥 ∈ ≃𝑟 ↔ ∃ 𝑟𝑠 ( 𝑥 = ⟨ 𝑟 , 𝑠 ⟩ ∧ 𝑟𝑟 𝑠 ) ) )
6 4 5 ax-mp ( 𝑥 ∈ ≃𝑟 ↔ ∃ 𝑟𝑠 ( 𝑥 = ⟨ 𝑟 , 𝑠 ⟩ ∧ 𝑟𝑟 𝑠 ) )
7 elopab ( 𝑥 ∈ { ⟨ 𝑟 , 𝑠 ⟩ ∣ ( ( 𝑟 ∈ Ring ∧ 𝑠 ∈ Ring ) ∧ ∃ 𝑓 𝑓 ∈ ( 𝑟 RingIso 𝑠 ) ) } ↔ ∃ 𝑟𝑠 ( 𝑥 = ⟨ 𝑟 , 𝑠 ⟩ ∧ ( ( 𝑟 ∈ Ring ∧ 𝑠 ∈ Ring ) ∧ ∃ 𝑓 𝑓 ∈ ( 𝑟 RingIso 𝑠 ) ) ) )
8 3 6 7 3bitr4i ( 𝑥 ∈ ≃𝑟𝑥 ∈ { ⟨ 𝑟 , 𝑠 ⟩ ∣ ( ( 𝑟 ∈ Ring ∧ 𝑠 ∈ Ring ) ∧ ∃ 𝑓 𝑓 ∈ ( 𝑟 RingIso 𝑠 ) ) } )
9 8 eqriv 𝑟 = { ⟨ 𝑟 , 𝑠 ⟩ ∣ ( ( 𝑟 ∈ Ring ∧ 𝑠 ∈ Ring ) ∧ ∃ 𝑓 𝑓 ∈ ( 𝑟 RingIso 𝑠 ) ) }