Metamath Proof Explorer


Theorem diveq1

Description: Equality in terms of unit ratio. (Contributed by Stefan O'Rear, 27-Aug-2015)

Ref Expression
Assertion diveq1 ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐵 ≠ 0 ) → ( ( 𝐴 / 𝐵 ) = 1 ↔ 𝐴 = 𝐵 ) )

Proof

Step Hyp Ref Expression
1 ax-1cn 1 ∈ ℂ
2 divmul2 ( ( 𝐴 ∈ ℂ ∧ 1 ∈ ℂ ∧ ( 𝐵 ∈ ℂ ∧ 𝐵 ≠ 0 ) ) → ( ( 𝐴 / 𝐵 ) = 1 ↔ 𝐴 = ( 𝐵 · 1 ) ) )
3 1 2 mp3an2 ( ( 𝐴 ∈ ℂ ∧ ( 𝐵 ∈ ℂ ∧ 𝐵 ≠ 0 ) ) → ( ( 𝐴 / 𝐵 ) = 1 ↔ 𝐴 = ( 𝐵 · 1 ) ) )
4 3 3impb ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐵 ≠ 0 ) → ( ( 𝐴 / 𝐵 ) = 1 ↔ 𝐴 = ( 𝐵 · 1 ) ) )
5 simp2 ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐵 ≠ 0 ) → 𝐵 ∈ ℂ )
6 5 mulid1d ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐵 ≠ 0 ) → ( 𝐵 · 1 ) = 𝐵 )
7 6 eqeq2d ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐵 ≠ 0 ) → ( 𝐴 = ( 𝐵 · 1 ) ↔ 𝐴 = 𝐵 ) )
8 4 7 bitrd ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐵 ≠ 0 ) → ( ( 𝐴 / 𝐵 ) = 1 ↔ 𝐴 = 𝐵 ) )