Metamath Proof Explorer


Theorem drnf1v

Description: Formula-building lemma for use with the Distinctor Reduction Theorem. Version of drnf1 with a disjoint variable condition, which does not require ax-13 . (Contributed by Mario Carneiro, 4-Oct-2016) (Revised by BJ, 17-Jun-2019)

Ref Expression
Hypothesis dral1v.1 ( ∀ 𝑥 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
Assertion drnf1v ( ∀ 𝑥 𝑥 = 𝑦 → ( Ⅎ 𝑥 𝜑 ↔ Ⅎ 𝑦 𝜓 ) )

Proof

Step Hyp Ref Expression
1 dral1v.1 ( ∀ 𝑥 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
2 1 dral1v ( ∀ 𝑥 𝑥 = 𝑦 → ( ∀ 𝑥 𝜑 ↔ ∀ 𝑦 𝜓 ) )
3 1 2 imbi12d ( ∀ 𝑥 𝑥 = 𝑦 → ( ( 𝜑 → ∀ 𝑥 𝜑 ) ↔ ( 𝜓 → ∀ 𝑦 𝜓 ) ) )
4 3 dral1v ( ∀ 𝑥 𝑥 = 𝑦 → ( ∀ 𝑥 ( 𝜑 → ∀ 𝑥 𝜑 ) ↔ ∀ 𝑦 ( 𝜓 → ∀ 𝑦 𝜓 ) ) )
5 nf5 ( Ⅎ 𝑥 𝜑 ↔ ∀ 𝑥 ( 𝜑 → ∀ 𝑥 𝜑 ) )
6 nf5 ( Ⅎ 𝑦 𝜓 ↔ ∀ 𝑦 ( 𝜓 → ∀ 𝑦 𝜓 ) )
7 4 5 6 3bitr4g ( ∀ 𝑥 𝑥 = 𝑦 → ( Ⅎ 𝑥 𝜑 ↔ Ⅎ 𝑦 𝜓 ) )