Metamath Proof Explorer


Theorem eceq1i

Description: Equality theorem for C -coset of A and C -coset of B , inference version. (Contributed by Peter Mazsa, 11-May-2021)

Ref Expression
Hypothesis eceq1i.1 𝐴 = 𝐵
Assertion eceq1i [ 𝐴 ] 𝐶 = [ 𝐵 ] 𝐶

Proof

Step Hyp Ref Expression
1 eceq1i.1 𝐴 = 𝐵
2 eceq1 ( 𝐴 = 𝐵 → [ 𝐴 ] 𝐶 = [ 𝐵 ] 𝐶 )
3 1 2 ax-mp [ 𝐴 ] 𝐶 = [ 𝐵 ] 𝐶