Metamath Proof Explorer


Theorem eceq1i

Description: Equality theorem for C -coset of A and C -coset of B , inference version. (Contributed by Peter Mazsa, 11-May-2021)

Ref Expression
Hypothesis eceq1i.1
|- A = B
Assertion eceq1i
|- [ A ] C = [ B ] C

Proof

Step Hyp Ref Expression
1 eceq1i.1
 |-  A = B
2 eceq1
 |-  ( A = B -> [ A ] C = [ B ] C )
3 1 2 ax-mp
 |-  [ A ] C = [ B ] C