Theorem efval2

Description: Value of the exponential function. (Contributed by Mario Carneiro, 29-Apr-2014)

	Ref	Expression
Hypothesis	efcvg.1	⊢ 𝐹 = ( 𝑛 ∈ ℕ0 ↦ ( ( 𝐴 ↑ 𝑛 ) / ( ! ‘ 𝑛 ) ) )
Assertion	efval2	⊢ ( 𝐴 ∈ ℂ → ( exp ‘ 𝐴 ) = Σ 𝑘 ∈ ℕ0 ( 𝐹 ‘ 𝑘 ) )

Proof

Step	Hyp	Ref	Expression
1		efcvg.1	⊢ 𝐹 = ( 𝑛 ∈ ℕ0 ↦ ( ( 𝐴 ↑ 𝑛 ) / ( ! ‘ 𝑛 ) ) )
2		efval	⊢ ( 𝐴 ∈ ℂ → ( exp ‘ 𝐴 ) = Σ 𝑘 ∈ ℕ0 ( ( 𝐴 ↑ 𝑘 ) / ( ! ‘ 𝑘 ) ) )
3	1	eftval	⊢ ( 𝑘 ∈ ℕ0 → ( 𝐹 ‘ 𝑘 ) = ( ( 𝐴 ↑ 𝑘 ) / ( ! ‘ 𝑘 ) ) )
4	3	sumeq2i	⊢ Σ 𝑘 ∈ ℕ0 ( 𝐹 ‘ 𝑘 ) = Σ 𝑘 ∈ ℕ0 ( ( 𝐴 ↑ 𝑘 ) / ( ! ‘ 𝑘 ) )
5	2 4	eqtr4di	⊢ ( 𝐴 ∈ ℂ → ( exp ‘ 𝐴 ) = Σ 𝑘 ∈ ℕ0 ( 𝐹 ‘ 𝑘 ) )