Metamath Proof Explorer


Theorem elhf3

Description: A set is hereditarily finite if and only if it is finite and all its members are hereditarily finite. (Contributed by Eric Schmidt, 8-Sep-2026)

Ref Expression
Assertion elhf3 ( 𝐴 ∈ Hf ↔ ( 𝐴 ∈ Fin ∧ 𝐴 ⊆ Hf ) )

Proof

Step Hyp Ref Expression
1 hffi ( 𝐴 ∈ Hf → 𝐴 ∈ Fin )
2 hfelhf ( ( 𝑥𝐴𝐴 ∈ Hf ) → 𝑥 ∈ Hf )
3 2 expcom ( 𝐴 ∈ Hf → ( 𝑥𝐴𝑥 ∈ Hf ) )
4 3 ssrdv ( 𝐴 ∈ Hf → 𝐴 ⊆ Hf )
5 1 4 jca ( 𝐴 ∈ Hf → ( 𝐴 ∈ Fin ∧ 𝐴 ⊆ Hf ) )
6 eleq1 ( 𝑥 = ∅ → ( 𝑥 ∈ Hf ↔ ∅ ∈ Hf ) )
7 eleq1 ( 𝑥 = 𝑦 → ( 𝑥 ∈ Hf ↔ 𝑦 ∈ Hf ) )
8 eleq1 ( 𝑥 = ( 𝑦 ∪ { 𝑧 } ) → ( 𝑥 ∈ Hf ↔ ( 𝑦 ∪ { 𝑧 } ) ∈ Hf ) )
9 eleq1 ( 𝑥 = 𝐴 → ( 𝑥 ∈ Hf ↔ 𝐴 ∈ Hf ) )
10 0hf ∅ ∈ Hf
11 10 a1i ( ( 𝐴 ∈ Fin ∧ 𝐴 ⊆ Hf ) → ∅ ∈ Hf )
12 eldifi ( 𝑧 ∈ ( 𝐴𝑦 ) → 𝑧𝐴 )
13 ssel2 ( ( 𝐴 ⊆ Hf ∧ 𝑧𝐴 ) → 𝑧 ∈ Hf )
14 12 13 sylan2 ( ( 𝐴 ⊆ Hf ∧ 𝑧 ∈ ( 𝐴𝑦 ) ) → 𝑧 ∈ Hf )
15 hfadj ( ( 𝑦 ∈ Hf ∧ 𝑧 ∈ Hf ) → ( 𝑦 ∪ { 𝑧 } ) ∈ Hf )
16 15 expcom ( 𝑧 ∈ Hf → ( 𝑦 ∈ Hf → ( 𝑦 ∪ { 𝑧 } ) ∈ Hf ) )
17 14 16 syl ( ( 𝐴 ⊆ Hf ∧ 𝑧 ∈ ( 𝐴𝑦 ) ) → ( 𝑦 ∈ Hf → ( 𝑦 ∪ { 𝑧 } ) ∈ Hf ) )
18 17 ad2ant2l ( ( ( 𝐴 ∈ Fin ∧ 𝐴 ⊆ Hf ) ∧ ( 𝑦𝐴𝑧 ∈ ( 𝐴𝑦 ) ) ) → ( 𝑦 ∈ Hf → ( 𝑦 ∪ { 𝑧 } ) ∈ Hf ) )
19 simpl ( ( 𝐴 ∈ Fin ∧ 𝐴 ⊆ Hf ) → 𝐴 ∈ Fin )
20 6 7 8 9 11 18 19 findcard2d ( ( 𝐴 ∈ Fin ∧ 𝐴 ⊆ Hf ) → 𝐴 ∈ Hf )
21 5 20 impbii ( 𝐴 ∈ Hf ↔ ( 𝐴 ∈ Fin ∧ 𝐴 ⊆ Hf ) )