Metamath Proof Explorer


Theorem eliin2

Description: Membership in indexed intersection. See eliincex for a counterexample showing that the precondition B =/= (/) cannot be simply dropped. eliin uses an alternative precondition (and it doesn't have a disjoint var constraint between B and x ; see eliin2f ). (Contributed by Glauco Siliprandi, 26-Jun-2021)

Ref Expression
Assertion eliin2 ( 𝐵 ≠ ∅ → ( 𝐴 𝑥𝐵 𝐶 ↔ ∀ 𝑥𝐵 𝐴𝐶 ) )

Proof

Step Hyp Ref Expression
1 nfcv 𝑥 𝐵
2 1 eliin2f ( 𝐵 ≠ ∅ → ( 𝐴 𝑥𝐵 𝐶 ↔ ∀ 𝑥𝐵 𝐴𝐶 ) )