Metamath Proof Explorer


Theorem eliin2f

Description: Membership in indexed intersection. (Contributed by Glauco Siliprandi, 26-Jun-2021)

Ref Expression
Hypothesis eliin2f.1 𝑥 𝐵
Assertion eliin2f ( 𝐵 ≠ ∅ → ( 𝐴 𝑥𝐵 𝐶 ↔ ∀ 𝑥𝐵 𝐴𝐶 ) )

Proof

Step Hyp Ref Expression
1 eliin2f.1 𝑥 𝐵
2 eliin ( 𝐴 ∈ V → ( 𝐴 𝑥𝐵 𝐶 ↔ ∀ 𝑥𝐵 𝐴𝐶 ) )
3 2 adantl ( ( 𝐵 ≠ ∅ ∧ 𝐴 ∈ V ) → ( 𝐴 𝑥𝐵 𝐶 ↔ ∀ 𝑥𝐵 𝐴𝐶 ) )
4 prcnel ( ¬ 𝐴 ∈ V → ¬ 𝐴 𝑥𝐵 𝐶 )
5 4 adantl ( ( 𝐵 ≠ ∅ ∧ ¬ 𝐴 ∈ V ) → ¬ 𝐴 𝑥𝐵 𝐶 )
6 n0 ( 𝐵 ≠ ∅ ↔ ∃ 𝑦 𝑦𝐵 )
7 6 birani ( ( 𝐵 ≠ ∅ ∧ ¬ 𝐴 ∈ V ) → ∃ 𝑦 𝑦𝐵 )
8 prcnel ( ¬ 𝐴 ∈ V → ¬ 𝐴 𝑦 / 𝑥 𝐶 )
9 8 a1d ( ¬ 𝐴 ∈ V → ( 𝑦𝐵 → ¬ 𝐴 𝑦 / 𝑥 𝐶 ) )
10 9 adantl ( ( 𝐵 ≠ ∅ ∧ ¬ 𝐴 ∈ V ) → ( 𝑦𝐵 → ¬ 𝐴 𝑦 / 𝑥 𝐶 ) )
11 10 ancld ( ( 𝐵 ≠ ∅ ∧ ¬ 𝐴 ∈ V ) → ( 𝑦𝐵 → ( 𝑦𝐵 ∧ ¬ 𝐴 𝑦 / 𝑥 𝐶 ) ) )
12 11 eximdv ( ( 𝐵 ≠ ∅ ∧ ¬ 𝐴 ∈ V ) → ( ∃ 𝑦 𝑦𝐵 → ∃ 𝑦 ( 𝑦𝐵 ∧ ¬ 𝐴 𝑦 / 𝑥 𝐶 ) ) )
13 7 12 mpd ( ( 𝐵 ≠ ∅ ∧ ¬ 𝐴 ∈ V ) → ∃ 𝑦 ( 𝑦𝐵 ∧ ¬ 𝐴 𝑦 / 𝑥 𝐶 ) )
14 df-rex ( ∃ 𝑦𝐵 ¬ 𝐴 𝑦 / 𝑥 𝐶 ↔ ∃ 𝑦 ( 𝑦𝐵 ∧ ¬ 𝐴 𝑦 / 𝑥 𝐶 ) )
15 13 14 sylibr ( ( 𝐵 ≠ ∅ ∧ ¬ 𝐴 ∈ V ) → ∃ 𝑦𝐵 ¬ 𝐴 𝑦 / 𝑥 𝐶 )
16 nfcv 𝑦 𝐵
17 nfv 𝑦 ¬ 𝐴𝐶
18 nfcsb1v 𝑥 𝑦 / 𝑥 𝐶
19 18 nfel2 𝑥 𝐴 𝑦 / 𝑥 𝐶
20 19 nfn 𝑥 ¬ 𝐴 𝑦 / 𝑥 𝐶
21 csbeq1a ( 𝑥 = 𝑦𝐶 = 𝑦 / 𝑥 𝐶 )
22 21 eleq2d ( 𝑥 = 𝑦 → ( 𝐴𝐶𝐴 𝑦 / 𝑥 𝐶 ) )
23 22 notbid ( 𝑥 = 𝑦 → ( ¬ 𝐴𝐶 ↔ ¬ 𝐴 𝑦 / 𝑥 𝐶 ) )
24 1 16 17 20 23 cbvrexfw ( ∃ 𝑥𝐵 ¬ 𝐴𝐶 ↔ ∃ 𝑦𝐵 ¬ 𝐴 𝑦 / 𝑥 𝐶 )
25 15 24 sylibr ( ( 𝐵 ≠ ∅ ∧ ¬ 𝐴 ∈ V ) → ∃ 𝑥𝐵 ¬ 𝐴𝐶 )
26 rexnal ( ∃ 𝑥𝐵 ¬ 𝐴𝐶 ↔ ¬ ∀ 𝑥𝐵 𝐴𝐶 )
27 25 26 sylib ( ( 𝐵 ≠ ∅ ∧ ¬ 𝐴 ∈ V ) → ¬ ∀ 𝑥𝐵 𝐴𝐶 )
28 5 27 2falsed ( ( 𝐵 ≠ ∅ ∧ ¬ 𝐴 ∈ V ) → ( 𝐴 𝑥𝐵 𝐶 ↔ ∀ 𝑥𝐵 𝐴𝐶 ) )
29 3 28 pm2.61dan ( 𝐵 ≠ ∅ → ( 𝐴 𝑥𝐵 𝐶 ↔ ∀ 𝑥𝐵 𝐴𝐶 ) )