Metamath Proof Explorer


Theorem elinti

Description: Membership in class intersection. (Contributed by NM, 14-Oct-1999) (Proof shortened by Andrew Salmon, 9-Jul-2011)

Ref Expression
Assertion elinti ( 𝐴 ∈ ∩ 𝐵 → ( 𝐶 ∈ 𝐵 → 𝐴 ∈ 𝐶 ) )

Proof

Step Hyp Ref Expression
1 elintg ⊢ ( 𝐴 ∈ ∩ 𝐵 → ( 𝐴 ∈ ∩ 𝐵 ↔ ∀ 𝑥 ∈ 𝐵 𝐴 ∈ 𝑥 ) )
2 eleq2 ⊢ ( 𝑥 = 𝐶 → ( 𝐴 ∈ 𝑥 ↔ 𝐴 ∈ 𝐶 ) )
3 2 rspccv ⊢ ( ∀ 𝑥 ∈ 𝐵 𝐴 ∈ 𝑥 → ( 𝐶 ∈ 𝐵 → 𝐴 ∈ 𝐶 ) )
4 1 3 biimtrdi ⊢ ( 𝐴 ∈ ∩ 𝐵 → ( 𝐴 ∈ ∩ 𝐵 → ( 𝐶 ∈ 𝐵 → 𝐴 ∈ 𝐶 ) ) )
5 4 pm2.43i ⊢ ( 𝐴 ∈ ∩ 𝐵 → ( 𝐶 ∈ 𝐵 → 𝐴 ∈ 𝐶 ) )