Metamath Proof Explorer


Theorem elintg

Description: Membership in class intersection, with the sethood requirement expressed as an antecedent. (Contributed by NM, 20-Nov-2003) (Proof shortened by JJ, 26-Jul-2021)

Ref Expression
Assertion elintg ( 𝐴 ∈ 𝑉 → ( 𝐴 ∈ ∩ 𝐵 ↔ ∀ 𝑥 ∈ 𝐵 𝐴 ∈ 𝑥 ) )

Proof

Step Hyp Ref Expression
1 eleq1 ⊢ ( 𝑦 = 𝐴 → ( 𝑦 ∈ 𝑥 ↔ 𝐴 ∈ 𝑥 ) )
2 1 ralbidv ⊢ ( 𝑦 = 𝐴 → ( ∀ 𝑥 ∈ 𝐵 𝑦 ∈ 𝑥 ↔ ∀ 𝑥 ∈ 𝐵 𝐴 ∈ 𝑥 ) )
3 dfint2 ⊢ ∩ 𝐵 = { 𝑦 ∣ ∀ 𝑥 ∈ 𝐵 𝑦 ∈ 𝑥 }
4 2 3 elab2g ⊢ ( 𝐴 ∈ 𝑉 → ( 𝐴 ∈ ∩ 𝐵 ↔ ∀ 𝑥 ∈ 𝐵 𝐴 ∈ 𝑥 ) )