Metamath Proof Explorer


Theorem elqsecl

Description: Membership in a quotient set by an equivalence class according to .~ . (Contributed by Alexander van der Vekens, 12-Apr-2018) (Revised by AV, 30-Apr-2021)

Ref Expression
Assertion elqsecl ( 𝐵 ∈ 𝑋 → ( 𝐵 ∈ ( 𝑊 / ∼ ) ↔ ∃ 𝑥 ∈ 𝑊 𝐵 = { 𝑦 ∣ 𝑥 ∼ 𝑦 } ) )

Proof

Step Hyp Ref Expression
1 elqsg ⊢ ( 𝐵 ∈ 𝑋 → ( 𝐵 ∈ ( 𝑊 / ∼ ) ↔ ∃ 𝑥 ∈ 𝑊 𝐵 = [ 𝑥 ] ∼ ) )
2 vex ⊢ 𝑥 ∈ V
3 dfec2 ⊢ ( 𝑥 ∈ V → [ 𝑥 ] ∼ = { 𝑦 ∣ 𝑥 ∼ 𝑦 } )
4 2 3 mp1i ⊢ ( 𝐵 ∈ 𝑋 → [ 𝑥 ] ∼ = { 𝑦 ∣ 𝑥 ∼ 𝑦 } )
5 4 eqeq2d ⊢ ( 𝐵 ∈ 𝑋 → ( 𝐵 = [ 𝑥 ] ∼ ↔ 𝐵 = { 𝑦 ∣ 𝑥 ∼ 𝑦 } ) )
6 5 rexbidv ⊢ ( 𝐵 ∈ 𝑋 → ( ∃ 𝑥 ∈ 𝑊 𝐵 = [ 𝑥 ] ∼ ↔ ∃ 𝑥 ∈ 𝑊 𝐵 = { 𝑦 ∣ 𝑥 ∼ 𝑦 } ) )
7 1 6 bitrd ⊢ ( 𝐵 ∈ 𝑋 → ( 𝐵 ∈ ( 𝑊 / ∼ ) ↔ ∃ 𝑥 ∈ 𝑊 𝐵 = { 𝑦 ∣ 𝑥 ∼ 𝑦 } ) )