Metamath Proof Explorer


Theorem elsigass

Description: An element of a sigma-algebra is a subset of the base set. (Contributed by Thierry Arnoux, 6-Jun-2017)

Ref Expression
Assertion elsigass ( ( 𝑆 ∈ ∪ ran sigAlgebra ∧ 𝐴 ∈ 𝑆 ) → 𝐴 ⊆ ∪ 𝑆 )

Proof

Step Hyp Ref Expression
1 sgon ⊢ ( 𝑆 ∈ ∪ ran sigAlgebra → 𝑆 ∈ ( sigAlgebra ‘ ∪ 𝑆 ) )
2 sigasspw ⊢ ( 𝑆 ∈ ( sigAlgebra ‘ ∪ 𝑆 ) → 𝑆 ⊆ 𝒫 ∪ 𝑆 )
3 1 2 syl ⊢ ( 𝑆 ∈ ∪ ran sigAlgebra → 𝑆 ⊆ 𝒫 ∪ 𝑆 )
4 3 sselda ⊢ ( ( 𝑆 ∈ ∪ ran sigAlgebra ∧ 𝐴 ∈ 𝑆 ) → 𝐴 ∈ 𝒫 ∪ 𝑆 )
5 4 elpwid ⊢ ( ( 𝑆 ∈ ∪ ran sigAlgebra ∧ 𝐴 ∈ 𝑆 ) → 𝐴 ⊆ ∪ 𝑆 )