Metamath Proof Explorer


Theorem eqeng

Description: Equality implies equinumerosity. (Contributed by NM, 26-Oct-2003)

Ref Expression
Assertion eqeng ( 𝐴 ∈ 𝑉 → ( 𝐴 = 𝐵 → 𝐴 ≈ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 enrefg ⊢ ( 𝐴 ∈ 𝑉 → 𝐴 ≈ 𝐴 )
2 breq2 ⊢ ( 𝐴 = 𝐵 → ( 𝐴 ≈ 𝐴 ↔ 𝐴 ≈ 𝐵 ) )
3 1 2 syl5ibcom ⊢ ( 𝐴 ∈ 𝑉 → ( 𝐴 = 𝐵 → 𝐴 ≈ 𝐵 ) )