Metamath Proof Explorer
		
		
		
		Description:  A chained subclass and equality deduction.  (Contributed by Mario
       Carneiro, 2-Jan-2017)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | eqsstrrdi.1 | ⊢ ( 𝜑  →  𝐵  =  𝐴 ) | 
					
						|  |  | eqsstrrdi.2 | ⊢ 𝐵  ⊆  𝐶 | 
				
					|  | Assertion | eqsstrrdi | ⊢  ( 𝜑  →  𝐴  ⊆  𝐶 ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | eqsstrrdi.1 | ⊢ ( 𝜑  →  𝐵  =  𝐴 ) | 
						
							| 2 |  | eqsstrrdi.2 | ⊢ 𝐵  ⊆  𝐶 | 
						
							| 3 | 1 | eqcomd | ⊢ ( 𝜑  →  𝐴  =  𝐵 ) | 
						
							| 4 | 3 2 | eqsstrdi | ⊢ ( 𝜑  →  𝐴  ⊆  𝐶 ) |