Metamath Proof Explorer


Theorem eqsstri

Description: Substitution of equality into a subclass relationship. (Contributed by NM, 16-Jul-1995)

Ref Expression
Hypotheses eqsstr.1 ⊢ 𝐴 = 𝐵
eqsstr.2 ⊢ 𝐵 ⊆ 𝐶
Assertion eqsstri 𝐴 ⊆ 𝐶

Proof

Step Hyp Ref Expression
1 eqsstr.1 ⊢ 𝐴 = 𝐵
2 eqsstr.2 ⊢ 𝐵 ⊆ 𝐶
3 1 sseq1i ⊢ ( 𝐴 ⊆ 𝐶 ↔ 𝐵 ⊆ 𝐶 )
4 2 3 mpbir ⊢ 𝐴 ⊆ 𝐶